Base | Representation |
---|---|
bin | 1100001001010111010111… |
… | …0101101111011011111111 |
3 | 1202021201200000201202100222 |
4 | 3002111311311233123333 |
5 | 3222302100232023341 |
6 | 44223114413011555 |
7 | 2545604046632033 |
oct | 302256565573377 |
9 | 52251600652328 |
10 | 13355030345471 |
11 | 4289922513051 |
12 | 15b8364783bbb |
13 | 75b4b277b909 |
14 | 34255b9b81c3 |
15 | 1825dd13844b |
hex | c2575d6f6ff |
13355030345471 has 2 divisors, whose sum is σ = 13355030345472. Its totient is φ = 13355030345470.
The previous prime is 13355030345387. The next prime is 13355030345477. The reversal of 13355030345471 is 17454303055331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13355030345471 is a prime.
It is a super-3 number, since 3×133550303454713 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13355030345477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6677515172735 + 6677515172736.
It is an arithmetic number, because the mean of its divisors is an integer number (6677515172736).
Almost surely, 213355030345471 is an apocalyptic number.
13355030345471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13355030345471 is an equidigital number, since it uses as much as digits as its factorization.
13355030345471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134000, while the sum is 44.
The spelling of 13355030345471 in words is "thirteen trillion, three hundred fifty-five billion, thirty million, three hundred forty-five thousand, four hundred seventy-one".
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