Base | Representation |
---|---|
bin | 111110001100101001… |
… | …0010011000010010111 |
3 | 110202202121011020212011 |
4 | 1330121102103002113 |
5 | 4142021430310033 |
6 | 141205502205051 |
7 | 12435642036061 |
oct | 1743122230227 |
9 | 422677136764 |
10 | 133568213143 |
11 | 51711857512 |
12 | 21a77883787 |
13 | c798205561 |
14 | 6671342731 |
15 | 371b246ccd |
hex | 1f19493097 |
133568213143 has 2 divisors, whose sum is σ = 133568213144. Its totient is φ = 133568213142.
The previous prime is 133568213123. The next prime is 133568213173. The reversal of 133568213143 is 341312865331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133568213143 - 25 = 133568213111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133568213096 and 133568213105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133568213113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66784106571 + 66784106572.
It is an arithmetic number, because the mean of its divisors is an integer number (66784106572).
Almost surely, 2133568213143 is an apocalyptic number.
133568213143 is a deficient number, since it is larger than the sum of its proper divisors (1).
133568213143 is an equidigital number, since it uses as much as digits as its factorization.
133568213143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 40.
The spelling of 133568213143 in words is "one hundred thirty-three billion, five hundred sixty-eight million, two hundred thirteen thousand, one hundred forty-three".
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