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133609251891757 is a prime number
BaseRepresentation
bin11110011000010001010011…
…111111110110101000101101
3122112001220211111012102020211
4132120101103333312220231
5120003023221441014012
61152055124251542421
740066643546456125
oct3630212377665055
9575056744172224
10133609251891757
1139632402563734
1212b9a45015aa11
1359723b5748345
1424dca17d9dc85
15106a73aee16a7
hex798453ff6a2d

133609251891757 has 2 divisors, whose sum is σ = 133609251891758. Its totient is φ = 133609251891756.

The previous prime is 133609251891697. The next prime is 133609251891767. The reversal of 133609251891757 is 757198152906331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133608377270281 + 874621476 = 11558909^2 + 29574^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133609251891757 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133609251891692 and 133609251891701.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133609251891767) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66804625945878 + 66804625945879.

It is an arithmetic number, because the mean of its divisors is an integer number (66804625945879).

Almost surely, 2133609251891757 is an apocalyptic number.

It is an amenable number.

133609251891757 is a deficient number, since it is larger than the sum of its proper divisors (1).

133609251891757 is an equidigital number, since it uses as much as digits as its factorization.

133609251891757 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 85730400, while the sum is 67.

The spelling of 133609251891757 in words is "one hundred thirty-three trillion, six hundred nine billion, two hundred fifty-one million, eight hundred ninety-one thousand, seven hundred fifty-seven".