Base | Representation |
---|---|
bin | 1100001001110000000100… |
… | …0111100101111001010111 |
3 | 1202022100210012101222212112 |
4 | 3002130001013211321113 |
5 | 3222404140434302203 |
6 | 44230132432541235 |
7 | 2546230304162414 |
oct | 302340107457127 |
9 | 52270705358775 |
10 | 13361662025303 |
11 | 429171596a289 |
12 | 15b96b56b181b |
13 | 75bccb685a17 |
14 | 3429ca65910b |
15 | 18287a44a6d8 |
hex | c27011e5e57 |
13361662025303 has 2 divisors, whose sum is σ = 13361662025304. Its totient is φ = 13361662025302.
The previous prime is 13361662025279. The next prime is 13361662025311. The reversal of 13361662025303 is 30352026616331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13361662025303 - 218 = 13361661763159 is a prime.
It is a super-3 number, since 3×133616620253033 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13361662025203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6680831012651 + 6680831012652.
It is an arithmetic number, because the mean of its divisors is an integer number (6680831012652).
Almost surely, 213361662025303 is an apocalyptic number.
13361662025303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13361662025303 is an equidigital number, since it uses as much as digits as its factorization.
13361662025303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 349920, while the sum is 41.
The spelling of 13361662025303 in words is "thirteen trillion, three hundred sixty-one billion, six hundred sixty-two million, twenty-five thousand, three hundred three".
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