Base | Representation |
---|---|
bin | 11000111000111111… |
… | …11110100000101001 |
3 | 1021111021221002112222 |
4 | 30130133332200221 |
5 | 204331414441231 |
6 | 10050000243425 |
7 | 652102010033 |
oct | 143437764051 |
9 | 37437832488 |
10 | 13363046441 |
11 | 5738100638 |
12 | 270b310575 |
13 | 134c675294 |
14 | 90aa70c53 |
15 | 53326627b |
hex | 31c7fe829 |
13363046441 has 2 divisors, whose sum is σ = 13363046442. Its totient is φ = 13363046440.
The previous prime is 13363046423. The next prime is 13363046443. The reversal of 13363046441 is 14464036331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12213565225 + 1149481216 = 110515^2 + 33904^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13363046441 is a prime.
Together with 13363046443, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13363046443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6681523220 + 6681523221.
It is an arithmetic number, because the mean of its divisors is an integer number (6681523221).
Almost surely, 213363046441 is an apocalyptic number.
It is an amenable number.
13363046441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13363046441 is an equidigital number, since it uses as much as digits as its factorization.
13363046441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 62208, while the sum is 35.
The spelling of 13363046441 in words is "thirteen billion, three hundred sixty-three million, forty-six thousand, four hundred forty-one".
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