Base | Representation |
---|---|
bin | 11000111001001001… |
… | …00010000011111111 |
3 | 1021111101011202200112 |
4 | 30130210202003333 |
5 | 204332221200024 |
6 | 10050042020235 |
7 | 652115112461 |
oct | 143444420377 |
9 | 37441152615 |
10 | 13364240639 |
11 | 5738846882 |
12 | 270b7a767b |
13 | 134c9a29c9 |
14 | 90aca2131 |
15 | 53340000e |
hex | 31c9220ff |
13364240639 has 2 divisors, whose sum is σ = 13364240640. Its totient is φ = 13364240638.
The previous prime is 13364240629. The next prime is 13364240663. The reversal of 13364240639 is 93604246331.
13364240639 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13364240639 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13364240596 and 13364240605.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13364240629) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6682120319 + 6682120320.
It is an arithmetic number, because the mean of its divisors is an integer number (6682120320).
Almost surely, 213364240639 is an apocalyptic number.
13364240639 is a deficient number, since it is larger than the sum of its proper divisors (1).
13364240639 is an equidigital number, since it uses as much as digits as its factorization.
13364240639 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 279936, while the sum is 41.
The spelling of 13364240639 in words is "thirteen billion, three hundred sixty-four million, two hundred forty thousand, six hundred thirty-nine".
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