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133643435259097 is a prime number
BaseRepresentation
bin11110011000110001001001…
…011111000011010011011001
3122112012012001210020101210001
4132120301021133003103121
5120004103223411242342
61152122540244053001
740102263624343201
oct3630611137032331
9575165053211701
10133643435259097
1139645954143545
1212ba4bb0094161
1359756a271461a
14250053bc51401
15106b58c0118b7
hex798c497c34d9

133643435259097 has 2 divisors, whose sum is σ = 133643435259098. Its totient is φ = 133643435259096.

The previous prime is 133643435259029. The next prime is 133643435259107. The reversal of 133643435259097 is 790952534346331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94101271737561 + 39542163521536 = 9700581^2 + 6288256^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133643435259097 is a prime.

It is not a weakly prime, because it can be changed into another prime (133643435254097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66821717629548 + 66821717629549.

It is an arithmetic number, because the mean of its divisors is an integer number (66821717629549).

Almost surely, 2133643435259097 is an apocalyptic number.

It is an amenable number.

133643435259097 is a deficient number, since it is larger than the sum of its proper divisors (1).

133643435259097 is an equidigital number, since it uses as much as digits as its factorization.

133643435259097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 220449600, while the sum is 64.

The spelling of 133643435259097 in words is "one hundred thirty-three trillion, six hundred forty-three billion, four hundred thirty-five million, two hundred fifty-nine thousand, ninety-seven".