Base | Representation |
---|---|
bin | 11110011000110001001001… |
… | …011111000101110000000001 |
3 | 122112012012001210020220112022 |
4 | 132120301021133011300001 |
5 | 120004103223412102441 |
6 | 1152122540244211225 |
7 | 40102263624414341 |
oct | 3630611137056001 |
9 | 575165053226468 |
10 | 133643435269121 |
11 | 39645954150028 |
12 | 12ba4bb0099b15 |
13 | 59756a271905b |
14 | 250053bc54d21 |
15 | 106b58c01484b |
hex | 798c497c5c01 |
133643435269121 has 2 divisors, whose sum is σ = 133643435269122. Its totient is φ = 133643435269120.
The previous prime is 133643435269087. The next prime is 133643435269163. The reversal of 133643435269121 is 121962534346331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 126352549642225 + 7290885626896 = 11240665^2 + 2700164^2 .
It is a cyclic number.
It is not a de Polignac number, because 133643435269121 - 214 = 133643435252737 is a prime.
It is a super-2 number, since 2×1336434352691212 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133643435269181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66821717634560 + 66821717634561.
It is an arithmetic number, because the mean of its divisors is an integer number (66821717634561).
Almost surely, 2133643435269121 is an apocalyptic number.
It is an amenable number.
133643435269121 is a deficient number, since it is larger than the sum of its proper divisors (1).
133643435269121 is an equidigital number, since it uses as much as digits as its factorization.
133643435269121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8398080, while the sum is 53.
The spelling of 133643435269121 in words is "one hundred thirty-three trillion, six hundred forty-three billion, four hundred thirty-five million, two hundred sixty-nine thousand, one hundred twenty-one".
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