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13365382155617 is a prime number
BaseRepresentation
bin1100001001111101111011…
…0110110000110101100001
31202022201101110111012021202
43002133132312300311201
53222434300312434432
644231545524130545
72546421425600402
oct302373666606541
952281343435252
1013365382155617
114293254879248
1215ba373536a55
1375c47230716b
14342c607599a9
151829e6d3b462
hexc27dedb0d61

13365382155617 has 2 divisors, whose sum is σ = 13365382155618. Its totient is φ = 13365382155616.

The previous prime is 13365382155613. The next prime is 13365382155673. The reversal of 13365382155617 is 71655128356331.

It is an a-pointer prime, because the next prime (13365382155673) can be obtained adding 13365382155617 to its sum of digits (56).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12874827598801 + 490554556816 = 3588151^2 + 700396^2 .

It is a cyclic number.

It is not a de Polignac number, because 13365382155617 - 22 = 13365382155613 is a prime.

It is not a weakly prime, because it can be changed into another prime (13365382155613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6682691077808 + 6682691077809.

It is an arithmetic number, because the mean of its divisors is an integer number (6682691077809).

Almost surely, 213365382155617 is an apocalyptic number.

It is an amenable number.

13365382155617 is a deficient number, since it is larger than the sum of its proper divisors (1).

13365382155617 is an equidigital number, since it uses as much as digits as its factorization.

13365382155617 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13608000, while the sum is 56.

The spelling of 13365382155617 in words is "thirteen trillion, three hundred sixty-five billion, three hundred eighty-two million, one hundred fifty-five thousand, six hundred seventeen".