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1336542001 is a prime number
BaseRepresentation
bin100111110101010…
…0000001100110001
310110010221100221121
41033222200030301
510214123321001
6340342422241
745056263624
oct11752401461
93403840847
101336542001
11626496873
12313731981
13183b90872
14c9713dbb
157c50c6a1
hex4faa0331

1336542001 has 2 divisors, whose sum is σ = 1336542002. Its totient is φ = 1336542000.

The previous prime is 1336541981. The next prime is 1336542013. The reversal of 1336542001 is 1002456331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 676052001 + 660490000 = 26001^2 + 25700^2 .

It is a cyclic number.

It is not a de Polignac number, because 1336542001 - 219 = 1336017713 is a prime.

It is not a weakly prime, because it can be changed into another prime (1336542301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 668271000 + 668271001.

It is an arithmetic number, because the mean of its divisors is an integer number (668271001).

Almost surely, 21336542001 is an apocalyptic number.

It is an amenable number.

1336542001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1336542001 is an equidigital number, since it uses as much as digits as its factorization.

1336542001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

The square root of 1336542001 is about 36558.7472569835. The cubic root of 1336542001 is about 1101.5246079447.

Adding to 1336542001 its reverse (1002456331), we get a palindrome (2338998332).

The spelling of 1336542001 in words is "one billion, three hundred thirty-six million, five hundred forty-two thousand, one".