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133676094193 is a prime number
BaseRepresentation
bin111110001111110110…
…1110101001011110001
3110210001010011011211121
41330133231311023301
54142232040003233
6141224314342241
712441422024065
oct1743755651361
9423033134747
10133676094193
1151767741104
1221aa7a2a981
13c7b46782b5
1466817c5aa5
15372595692d
hex1f1fb752f1

133676094193 has 2 divisors, whose sum is σ = 133676094194. Its totient is φ = 133676094192.

The previous prime is 133676094191. The next prime is 133676094257. The reversal of 133676094193 is 391490676331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 124501711104 + 9174383089 = 352848^2 + 95783^2 .

It is an emirp because it is prime and its reverse (391490676331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133676094193 - 21 = 133676094191 is a prime.

Together with 133676094191, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 133676094193.

It is not a weakly prime, because it can be changed into another prime (133676094191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66838047096 + 66838047097.

It is an arithmetic number, because the mean of its divisors is an integer number (66838047097).

Almost surely, 2133676094193 is an apocalyptic number.

It is an amenable number.

133676094193 is a deficient number, since it is larger than the sum of its proper divisors (1).

133676094193 is an equidigital number, since it uses as much as digits as its factorization.

133676094193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2204496, while the sum is 52.

The spelling of 133676094193 in words is "one hundred thirty-three billion, six hundred seventy-six million, ninety-four thousand, one hundred ninety-three".