Base | Representation |
---|---|
bin | 111110010000001101… |
… | …1100111010011001101 |
3 | 110210001221201221011002 |
4 | 1330200123213103031 |
5 | 4142243123032244 |
6 | 141225423510045 |
7 | 12441626031452 |
oct | 1744033472315 |
9 | 423057657132 |
10 | 133688095949 |
11 | 51773499211 |
12 | 21aaba58325 |
13 | c7b6cbb025 |
14 | 668322b829 |
15 | 3726a27a4e |
hex | 1f206e74cd |
133688095949 has 2 divisors, whose sum is σ = 133688095950. Its totient is φ = 133688095948.
The previous prime is 133688095883. The next prime is 133688095967. The reversal of 133688095949 is 949590886331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 68902575049 + 64785520900 = 262493^2 + 254530^2 .
It is an emirp because it is prime and its reverse (949590886331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133688095949 - 236 = 64968619213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133688095969) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66844047974 + 66844047975.
It is an arithmetic number, because the mean of its divisors is an integer number (66844047975).
Almost surely, 2133688095949 is an apocalyptic number.
It is an amenable number.
133688095949 is a deficient number, since it is larger than the sum of its proper divisors (1).
133688095949 is an equidigital number, since it uses as much as digits as its factorization.
133688095949 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50388480, while the sum is 65.
The spelling of 133688095949 in words is "one hundred thirty-three billion, six hundred eighty-eight million, ninety-five thousand, nine hundred forty-nine".
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