Base | Representation |
---|---|
bin | 1100001010001111010011… |
… | …1010001000010000101111 |
3 | 1202100011102120102010111112 |
4 | 3002203310322020100233 |
5 | 3223023324024312142 |
6 | 44234040450142235 |
7 | 2546645142160214 |
oct | 302436472102057 |
9 | 52304376363445 |
10 | 13370047104047 |
11 | 4295229041027 |
12 | 15bb25588197b |
13 | 75ca3691488a |
14 | 343184121b0b |
15 | 182bbb65d382 |
hex | c28f4e8842f |
13370047104047 has 4 divisors (see below), whose sum is σ = 13622312143800. Its totient is φ = 13117782064296.
The previous prime is 13370047103981. The next prime is 13370047104133. The reversal of 13370047104047 is 74040174007331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13370047104047 - 218 = 13370046841903 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13370047103995 and 13370047104013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13370047104347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126132519797 + ... + 126132519902.
It is an arithmetic number, because the mean of its divisors is an integer number (3405578035950).
Almost surely, 213370047104047 is an apocalyptic number.
13370047104047 is a deficient number, since it is larger than the sum of its proper divisors (252265039753).
13370047104047 is an equidigital number, since it uses as much as digits as its factorization.
13370047104047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 252265039752.
The product of its (nonzero) digits is 197568, while the sum is 41.
The spelling of 13370047104047 in words is "thirteen trillion, three hundred seventy billion, forty-seven million, one hundred four thousand, forty-seven".
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