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13370047104047 = 53252265039699
BaseRepresentation
bin1100001010001111010011…
…1010001000010000101111
31202100011102120102010111112
43002203310322020100233
53223023324024312142
644234040450142235
72546645142160214
oct302436472102057
952304376363445
1013370047104047
114295229041027
1215bb25588197b
1375ca3691488a
14343184121b0b
15182bbb65d382
hexc28f4e8842f

13370047104047 has 4 divisors (see below), whose sum is σ = 13622312143800. Its totient is φ = 13117782064296.

The previous prime is 13370047103981. The next prime is 13370047104133. The reversal of 13370047104047 is 74040174007331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13370047104047 - 218 = 13370046841903 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13370047103995 and 13370047104013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13370047104347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126132519797 + ... + 126132519902.

It is an arithmetic number, because the mean of its divisors is an integer number (3405578035950).

Almost surely, 213370047104047 is an apocalyptic number.

13370047104047 is a deficient number, since it is larger than the sum of its proper divisors (252265039753).

13370047104047 is an equidigital number, since it uses as much as digits as its factorization.

13370047104047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 252265039752.

The product of its (nonzero) digits is 197568, while the sum is 41.

The spelling of 13370047104047 in words is "thirteen trillion, three hundred seventy billion, forty-seven million, one hundred four thousand, forty-seven".

Divisors: 1 53 252265039699 13370047104047