Base | Representation |
---|---|
bin | 111010101111000010… |
… | …1011000001101110101 |
3 | 110001120101120220011022 |
4 | 1311132011120031311 |
5 | 4031304411113142 |
6 | 133540001350525 |
7 | 12053452504604 |
oct | 1653605301565 |
9 | 401511526138 |
10 | 126132519797 |
11 | 49546578aa9 |
12 | 20541638445 |
13 | bb818717cb |
14 | 61679ada3b |
15 | 34335686d2 |
hex | 1d5e158375 |
126132519797 has 2 divisors, whose sum is σ = 126132519798. Its totient is φ = 126132519796.
The previous prime is 126132519781. The next prime is 126132519827. The reversal of 126132519797 is 797915231621.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125401682641 + 730837156 = 354121^2 + 27034^2 .
It is a cyclic number.
It is not a de Polignac number, because 126132519797 - 24 = 126132519781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (126132519727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63066259898 + 63066259899.
It is an arithmetic number, because the mean of its divisors is an integer number (63066259899).
Almost surely, 2126132519797 is an apocalyptic number.
It is an amenable number.
126132519797 is a deficient number, since it is larger than the sum of its proper divisors (1).
126132519797 is an equidigital number, since it uses as much as digits as its factorization.
126132519797 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1428840, while the sum is 53.
The spelling of 126132519797 in words is "one hundred twenty-six billion, one hundred thirty-two million, five hundred nineteen thousand, seven hundred ninety-seven".
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