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13375828076069 is a prime number
BaseRepresentation
bin1100001010100100110101…
…1110110010011000100101
31202100201100110022221021102
43002221031132302120211
53223122143441413234
644240434240325445
72550241326501104
oct302511536623045
952321313287242
1013375828076069
114297725272958
1216003a9913885
137604484c3494
14343571bd803b
15182e08e2dc7e
hexc2a4d7b2625

13375828076069 has 2 divisors, whose sum is σ = 13375828076070. Its totient is φ = 13375828076068.

The previous prime is 13375828076057. The next prime is 13375828076099. The reversal of 13375828076069 is 96067082857331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13274815345444 + 101012730625 = 3643462^2 + 317825^2 .

It is a cyclic number.

It is not a de Polignac number, because 13375828076069 - 24 = 13375828076053 is a prime.

It is a super-2 number, since 2×133758280760692 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13375828075996 and 13375828076014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13375828076099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6687914038034 + 6687914038035.

It is an arithmetic number, because the mean of its divisors is an integer number (6687914038035).

Almost surely, 213375828076069 is an apocalyptic number.

It is an amenable number.

13375828076069 is a deficient number, since it is larger than the sum of its proper divisors (1).

13375828076069 is an equidigital number, since it uses as much as digits as its factorization.

13375828076069 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 91445760, while the sum is 65.

The spelling of 13375828076069 in words is "thirteen trillion, three hundred seventy-five billion, eight hundred twenty-eight million, seventy-six thousand, sixty-nine".