Base | Representation |
---|---|
bin | 10011011110010000100… |
… | …111010000000010111111 |
3 | 11201221000202002000102112 |
4 | 103132100213100002333 |
5 | 133411023211200003 |
6 | 2502424231044235 |
7 | 165451610100443 |
oct | 23362047200277 |
9 | 4657022060375 |
10 | 1338161037503 |
11 | 476569024514 |
12 | 19741751067b |
13 | 9925a1973c4 |
14 | 48aa581a823 |
15 | 24c1e2593d8 |
hex | 137909d00bf |
1338161037503 has 2 divisors, whose sum is σ = 1338161037504. Its totient is φ = 1338161037502.
The previous prime is 1338161037427. The next prime is 1338161037581. The reversal of 1338161037503 is 3057301618331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1338161037503 - 224 = 1338144260287 is a prime.
It is a super-2 number, since 2×13381610375032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1338161034503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 669080518751 + 669080518752.
It is an arithmetic number, because the mean of its divisors is an integer number (669080518752).
Almost surely, 21338161037503 is an apocalyptic number.
1338161037503 is a deficient number, since it is larger than the sum of its proper divisors (1).
1338161037503 is an equidigital number, since it uses as much as digits as its factorization.
1338161037503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 41.
The spelling of 1338161037503 in words is "one trillion, three hundred thirty-eight billion, one hundred sixty-one million, thirty-seven thousand, five hundred three".
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