Base | Representation |
---|---|
bin | 10011011110011011011… |
… | …001001001010011100010 |
3 | 11201221111100101020101101 |
4 | 103132123121021103202 |
5 | 133411411010424000 |
6 | 2502454211225014 |
7 | 165456234234142 |
oct | 23363331112342 |
9 | 4657440336341 |
10 | 1338341889250 |
11 | 476651119073 |
12 | 197467ba816a |
13 | 992887a8b82 |
14 | 48ac1856922 |
15 | 24c3007ee6a |
hex | 1379b6494e2 |
1338341889250 has 16 divisors (see below), whose sum is σ = 2505376017144. Its totient is φ = 535336755600.
The previous prime is 1338341889197. The next prime is 1338341889253. The reversal of 1338341889250 is 529881438331.
It can be written as a sum of positive squares in 4 ways, for example, as 536147592841 + 802194296409 = 732221^2 + 895653^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1338341889191 and 1338341889200.
It is not an unprimeable number, because it can be changed into a prime (1338341889253) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2676683529 + ... + 2676684028.
Almost surely, 21338341889250 is an apocalyptic number.
1338341889250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1338341889250 is a deficient number, since it is larger than the sum of its proper divisors (1167034127894).
1338341889250 is an equidigital number, since it uses as much as digits as its factorization.
1338341889250 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5353367574 (or 5353367564 counting only the distinct ones).
The product of its (nonzero) digits is 4976640, while the sum is 55.
The spelling of 1338341889250 in words is "one trillion, three hundred thirty-eight billion, three hundred forty-one million, eight hundred eighty-nine thousand, two hundred fifty".
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