133870763464769 has 2 divisors, whose sum is σ = 133870763464770. Its totient is φ = 133870763464768.

The previous prime is 133870763464673. The next prime is 133870763464771. The reversal of 133870763464769 is 967464367078331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121189009753744 + 12681753711025 = 11008588^2 + 3561145^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133870763464769 is a prime.

It is a super-2 number, since 2×133870763464769² (a number of 29 digits) contains 22 as substring.

Together with 133870763464771, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 133870763464696 and 133870763464705.

It is not a weakly prime, because it can be changed into another prime (133870763463769) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66935381732384 + 66935381732385.

It is an arithmetic number, because the mean of its divisors is an integer number (66935381732385).

Almost surely, 2^{133870763464769} is an apocalyptic number.

It is an amenable number.

133870763464769 is a deficient number, since it is larger than the sum of its proper divisors (1).

133870763464769 is an equidigital number, since it uses as much as digits as its factorization.

133870763464769 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304433152, while the sum is 74.

The spelling of 133870763464769 in words is "one hundred thirty-three trillion, eight hundred seventy billion, seven hundred sixty-three million, four hundred sixty-four thousand, seven hundred sixty-nine".