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133908174481 is a prime number
BaseRepresentation
bin111110010110110001…
…1001001011010010001
3110210122021212002010211
41330231203021122101
54143220443040411
6141303324524121
712450240463024
oct1745543113221
9423567762124
10133908174481
11518767454a4
1221b516b0641
13c820785403
1466a45591bb
15373aeeb221
hex1f2d8c9691

133908174481 has 2 divisors, whose sum is σ = 133908174482. Its totient is φ = 133908174480.

The previous prime is 133908174479. The next prime is 133908174551. The reversal of 133908174481 is 184471809331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129138890881 + 4769283600 = 359359^2 + 69060^2 .

It is a cyclic number.

It is not a de Polignac number, because 133908174481 - 21 = 133908174479 is a prime.

It is a super-2 number, since 2×1339081744812 (a number of 23 digits) contains 22 as substring.

Together with 133908174479, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (133908174181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66954087240 + 66954087241.

It is an arithmetic number, because the mean of its divisors is an integer number (66954087241).

Almost surely, 2133908174481 is an apocalyptic number.

It is an amenable number.

133908174481 is a deficient number, since it is larger than the sum of its proper divisors (1).

133908174481 is an equidigital number, since it uses as much as digits as its factorization.

133908174481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 580608, while the sum is 49.

The spelling of 133908174481 in words is "one hundred thirty-three billion, nine hundred eight million, one hundred seventy-four thousand, four hundred eighty-one".