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13391040000 = 29354132937
BaseRepresentation
bin11000111100010101…
…10000111000000000
31021120020121022111110
430132022300320000
5204411101240000
610052440243320
7652561650642
oct143612607000
937506538443
1013391040000
115751990608
122718770540
1313553c6c10
1491067a892
15535945850
hex31e2b0e00

13391040000 has 800 divisors, whose sum is σ = 51005797920. Its totient is φ = 3096576000.

The previous prime is 13391039999. The next prime is 13391040041. The reversal of 13391040000 is 4019331.

It is a tau number, because it is divible by the number of its divisors (800).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 361919982 + ... + 361920018.

Almost surely, 213391040000 is an apocalyptic number.

13391040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13391040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25502898960).

13391040000 is an abundant number, since it is smaller than the sum of its proper divisors (37614757920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13391040000 is an equidigital number, since it uses as much as digits as its factorization.

13391040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120 (or 89 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 13391040000 its reverse (4019331), we get a palindrome (13395059331).

The spelling of 13391040000 in words is "thirteen billion, three hundred ninety-one million, forty thousand".