Base | Representation |
---|---|
bin | 1100001011100010111100… |
… | …1110110000000110110110 |
3 | 1202102022101101022000121112 |
4 | 3002320233032300012312 |
5 | 3223410320102101032 |
6 | 44252232454515022 |
7 | 2551401434226566 |
oct | 302705716600666 |
9 | 52368341260545 |
10 | 13392500425142 |
11 | 42a3800391543 |
12 | 1603681365a72 |
13 | 761ba46570a7 |
14 | 3442b4186da6 |
15 | 1835829841b2 |
hex | c2e2f3b01b6 |
13392500425142 has 4 divisors (see below), whose sum is σ = 20088750637716. Its totient is φ = 6696250212570.
The previous prime is 13392500425133. The next prime is 13392500425159. The reversal of 13392500425142 is 24152400529331.
13392500425142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 13392500425142.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3348125106284 + ... + 3348125106287.
It is an arithmetic number, because the mean of its divisors is an integer number (5022187659429).
Almost surely, 213392500425142 is an apocalyptic number.
13392500425142 is a deficient number, since it is larger than the sum of its proper divisors (6696250212574).
13392500425142 is an equidigital number, since it uses as much as digits as its factorization.
13392500425142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6696250212573.
The product of its (nonzero) digits is 259200, while the sum is 41.
The spelling of 13392500425142 in words is "thirteen trillion, three hundred ninety-two billion, five hundred million, four hundred twenty-five thousand, one hundred forty-two".
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