13392500425133 has 2 divisors, whose sum is σ = 13392500425134. Its totient is φ = 13392500425132.

The previous prime is 13392500425127. The next prime is 13392500425159. The reversal of 13392500425133 is 33152400529331.

It is a happy number.

13392500425133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10984100607529 + 2408399817604 = 3314227^2 + 1551902^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13392500425133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13392500425193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6696250212566 + 6696250212567.

It is an arithmetic number, because the mean of its divisors is an integer number (6696250212567).

Almost surely, 2^{13392500425133} is an apocalyptic number.

It is an amenable number.

13392500425133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13392500425133 is an equidigital number, since it uses as much as digits as its factorization.

13392500425133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 291600, while the sum is 41.

The spelling of 13392500425133 in words is "thirteen trillion, three hundred ninety-two billion, five hundred million, four hundred twenty-five thousand, one hundred thirty-three".