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133993439497 is a prime number
BaseRepresentation
bin111110011001010100…
…0011010000100001001
3110210212020021222202101
41330302220122010021
54143404310030442
6141320012233401
712452324305051
oct1746250320411
9423766258671
10133993439497
115190a892355
1221b7616b861
13c83533a098
1466b19d2561
15374373ecb7
hex1f32a1a109

133993439497 has 2 divisors, whose sum is σ = 133993439498. Its totient is φ = 133993439496.

The previous prime is 133993439477. The next prime is 133993439509. The reversal of 133993439497 is 794934399331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131896806976 + 2096632521 = 363176^2 + 45789^2 .

It is an emirp because it is prime and its reverse (794934399331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133993439497 - 223 = 133985050889 is a prime.

It is a super-2 number, since 2×1339934394972 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133993439477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66996719748 + 66996719749.

It is an arithmetic number, because the mean of its divisors is an integer number (66996719749).

Almost surely, 2133993439497 is an apocalyptic number.

It is an amenable number.

133993439497 is a deficient number, since it is larger than the sum of its proper divisors (1).

133993439497 is an equidigital number, since it uses as much as digits as its factorization.

133993439497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 59521392, while the sum is 64.

The spelling of 133993439497 in words is "one hundred thirty-three billion, nine hundred ninety-three million, four hundred thirty-nine thousand, four hundred ninety-seven".