Base | Representation |
---|---|
bin | 10011011111111110001… |
… | …111100111010100010111 |
3 | 11202002202221001000102202 |
4 | 103133332033213110113 |
5 | 133423310041211002 |
6 | 2503330533355115 |
7 | 165545312626256 |
oct | 23377617472427 |
9 | 4662687030382 |
10 | 1340000335127 |
11 | 477322289aa3 |
12 | 19784b498a9b |
13 | 994912663ac |
14 | 48bdbc0279d |
15 | 24cca976502 |
hex | 137fe3e7517 |
1340000335127 has 2 divisors, whose sum is σ = 1340000335128. Its totient is φ = 1340000335126.
The previous prime is 1340000335117. The next prime is 1340000335139. The reversal of 1340000335127 is 7215330000431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340000335127 - 240 = 240488707351 is a prime.
It is a super-2 number, since 2×13400003351272 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1340000335127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340000335117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670000167563 + 670000167564.
It is an arithmetic number, because the mean of its divisors is an integer number (670000167564).
Almost surely, 21340000335127 is an apocalyptic number.
1340000335127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340000335127 is an equidigital number, since it uses as much as digits as its factorization.
1340000335127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 29.
Adding to 1340000335127 its reverse (7215330000431), we get a palindrome (8555330335558).
The spelling of 1340000335127 in words is "one trillion, three hundred forty billion, three hundred thirty-five thousand, one hundred twenty-seven".
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