Base | Representation |
---|---|
bin | 11000111101011001… |
… | …11111100011100111 |
3 | 1021120212111012011221 |
4 | 30132230333203213 |
5 | 204420400404111 |
6 | 10053400441211 |
7 | 653031142246 |
oct | 143654774347 |
9 | 37525435157 |
10 | 13400013031 |
11 | 5756a5a139 |
12 | 271b779207 |
13 | 13572191c2 |
14 | 91193495d |
15 | 536619371 |
hex | 31eb3f8e7 |
13400013031 has 2 divisors, whose sum is σ = 13400013032. Its totient is φ = 13400013030.
The previous prime is 13400013019. The next prime is 13400013041. The reversal of 13400013031 is 13031000431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13400013031 - 219 = 13399488743 is a prime.
It is a super-3 number, since 3×134000130313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 13400012996 and 13400013014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13400013041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700006515 + 6700006516.
It is an arithmetic number, because the mean of its divisors is an integer number (6700006516).
Almost surely, 213400013031 is an apocalyptic number.
13400013031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13400013031 is an equidigital number, since it uses as much as digits as its factorization.
13400013031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 13400013031 its reverse (13031000431), we get a palindrome (26431013462).
The spelling of 13400013031 in words is "thirteen billion, four hundred million, thirteen thousand, thirty-one".
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