Base | Representation |
---|---|
bin | 11110011101111101100000… |
… | …010011101010001110011110 |
3 | 122120110022012100000122010112 |
4 | 132131331200103222032132 |
5 | 120030430103402344314 |
6 | 1152554515503210022 |
7 | 40140126235313465 |
oct | 3635754023521636 |
9 | 576408170018115 |
10 | 134000300434334 |
11 | 3977323223a634 |
12 | 130421a55a6912 |
13 | 59a02356a12c9 |
14 | 25139133859dc |
15 | 10759c6aeb43e |
hex | 79df604ea39e |
134000300434334 has 4 divisors (see below), whose sum is σ = 201000450651504. Its totient is φ = 67000150217166.
The previous prime is 134000300434303. The next prime is 134000300434337. The reversal of 134000300434334 is 433434003000431.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 134000300434334.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134000300434337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33500075108582 + ... + 33500075108585.
It is an arithmetic number, because the mean of its divisors is an integer number (50250112662876).
Almost surely, 2134000300434334 is an apocalyptic number.
134000300434334 is a deficient number, since it is larger than the sum of its proper divisors (67000150217170).
134000300434334 is an equidigital number, since it uses as much as digits as its factorization.
134000300434334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67000150217169.
The product of its (nonzero) digits is 62208, while the sum is 32.
Adding to 134000300434334 its reverse (433434003000431), we get a palindrome (567434303434765).
The spelling of 134000300434334 in words is "one hundred thirty-four trillion, three hundred million, four hundred thirty-four thousand, three hundred thirty-four".
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