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134000301100 = 22521340003011
BaseRepresentation
bin111110011001100001…
…0100101010000101100
3110210212201012121002211
41330303002211100230
54143413034113400
6141320415300204
712452436523531
oct1746302452054
9423781177084
10134000301100
11519137495a6
1221b7851a664
13c8368a02c3
1466b289ad88
153744147dba
hex1f330a542c

134000301100 has 18 divisors (see below), whose sum is σ = 290780653604. Its totient is φ = 53600120400.

The previous prime is 134000301059. The next prime is 134000301109. The reversal of 134000301100 is 1103000431.

It is a super-2 number, since 2×1340003011002 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (134000301109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 670001406 + ... + 670001605.

Almost surely, 2134000301100 is an apocalyptic number.

134000301100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134000301100 is an abundant number, since it is smaller than the sum of its proper divisors (156780352504).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134000301100 is a wasteful number, since it uses less digits than its factorization.

134000301100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1340003025 (or 1340003018 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 134000301100 its reverse (1103000431), we get a palindrome (135103301531).

The spelling of 134000301100 in words is "one hundred thirty-four billion, three hundred one thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1340003011 2680006022 5360012044 6700015055 13400030110 26800060220 33500075275 67000150550 134000301100