13400054441 has 2 divisors, whose sum is σ = 13400054442. Its totient is φ = 13400054440.

The previous prime is 13400054407. The next prime is 13400054461. The reversal of 13400054441 is 14445000431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12790705216 + 609349225 = 113096^2 + 24685^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13400054441 is a prime.

It is a super-2 number, since 2×13400054441² (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13400054441.

It is not a weakly prime, because it can be changed into another prime (13400054461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700027220 + 6700027221.

It is an arithmetic number, because the mean of its divisors is an integer number (6700027221).

Almost surely, 2^13400054441 is an apocalyptic number.

It is an amenable number.

13400054441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13400054441 is an equidigital number, since it uses as much as digits as its factorization.

13400054441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 13400054441 its reverse (14445000431), we get a palindrome (27845054872).

The spelling of 13400054441 in words is "thirteen billion, four hundred million, fifty-four thousand, four hundred forty-one".