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13400400212142 = 232233400035357
BaseRepresentation
bin1100001100000000011000…
…0110000011000010101110
31202110001202221010210010020
43003000012012003002232
53224023004423242032
644300020414423010
72552101260266556
oct303000606030256
952401687123106
1013400400212142
1142a7094632429
121605106b01a66
137628631b0778
14344823406166
15183896286b2c
hexc30061830ae

13400400212142 has 8 divisors (see below), whose sum is σ = 26800800424296. Its totient is φ = 4466800070712.

The previous prime is 13400400212141. The next prime is 13400400212179. The reversal of 13400400212142 is 24121200400431.

It is a sphenic number, since it is the product of 3 distinct primes.

13400400212142 is an admirable number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13400400212141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1116700017673 + ... + 1116700017684.

It is an arithmetic number, because the mean of its divisors is an integer number (3350100053037).

Almost surely, 213400400212142 is an apocalyptic number.

13400400212142 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13400400212142 is a wasteful number, since it uses less digits than its factorization.

13400400212142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2233400035362.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 13400400212142 its reverse (24121200400431), we get a palindrome (37521600612573).

The spelling of 13400400212142 in words is "thirteen trillion, four hundred billion, four hundred million, two hundred twelve thousand, one hundred forty-two".

Divisors: 1 2 3 6 2233400035357 4466800070714 6700200106071 13400400212142