Base | Representation |
---|---|
bin | 1100001100000000011000… |
… | …0110011110011000001101 |
3 | 1202110001202221100110201011 |
4 | 3003000012012132120031 |
5 | 3224023004440332414 |
6 | 44300020421045221 |
7 | 2552101261244161 |
oct | 303000606363015 |
9 | 52401687313634 |
10 | 13400400324109 |
11 | 42a70946a9567 |
12 | 1605106b56811 |
13 | 76286321c716 |
14 | 344823434ca1 |
15 | 1838962a9dc4 |
hex | c300619e60d |
13400400324109 has 2 divisors, whose sum is σ = 13400400324110. Its totient is φ = 13400400324108.
The previous prime is 13400400324023. The next prime is 13400400324193. The reversal of 13400400324109 is 90142300400431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11424379720009 + 1976020604100 = 3379997^2 + 1405710^2 .
It is a cyclic number.
It is not a de Polignac number, because 13400400324109 - 213 = 13400400315917 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13400400327109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700200162054 + 6700200162055.
It is an arithmetic number, because the mean of its divisors is an integer number (6700200162055).
Almost surely, 213400400324109 is an apocalyptic number.
It is an amenable number.
13400400324109 is a deficient number, since it is larger than the sum of its proper divisors (1).
13400400324109 is an equidigital number, since it uses as much as digits as its factorization.
13400400324109 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
The spelling of 13400400324109 in words is "thirteen trillion, four hundred billion, four hundred million, three hundred twenty-four thousand, one hundred nine".
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