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134004400001110 = 2513400440000111
BaseRepresentation
bin11110011110000001010100…
…101010010001000001010110
3122120110200210001002012112001
4132132001110222101001112
5120031012002400013420
61153000434351145514
740140332645126302
oct3636012452210126
9576420701065461
10134004400001110
1139774a46349851
1213042b4a51529a
1359a0739b14272
142513bc1a16d02
151075b6698cb0a
hex79e054a91056

134004400001110 has 8 divisors (see below), whose sum is σ = 241207920002016. Its totient is φ = 53601760000440.

The previous prime is 134004400001047. The next prime is 134004400001113. The reversal of 134004400001110 is 11100004400431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134004400001113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6700220000046 + ... + 6700220000065.

It is an arithmetic number, because the mean of its divisors is an integer number (30150990000252).

Almost surely, 2134004400001110 is an apocalyptic number.

134004400001110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

134004400001110 is a deficient number, since it is larger than the sum of its proper divisors (107203520000906).

134004400001110 is a wasteful number, since it uses less digits than its factorization.

134004400001110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13400440000118.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 134004400001110 its reverse (11100004400431), we get a palindrome (145104404401541).

The spelling of 134004400001110 in words is "one hundred thirty-four trillion, four billion, four hundred million, one thousand, one hundred ten".

Divisors: 1 2 5 10 13400440000111 26800880000222 67002200000555 134004400001110