1340060131 has 2 divisors, whose sum is σ = 1340060132. Its totient is φ = 1340060130.

The previous prime is 1340060129. The next prime is 1340060153. The reversal of 1340060131 is 1310600431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1340060131 - 2¹ = 1340060129 is a prime.

It is a super-3 number, since 3×1340060131³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1340060129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1340060099 and 1340060108.

It is not a weakly prime, because it can be changed into another prime (1340060731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670030065 + 670030066.

It is an arithmetic number, because the mean of its divisors is an integer number (670030066).

Almost surely, 2^1340060131 is an apocalyptic number.

1340060131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340060131 is an equidigital number, since it uses as much as digits as its factorization.

1340060131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1340060131 is about 36606.8317531031. The cubic root of 1340060131 is about 1102.4902619619.

Adding to 1340060131 its reverse (1310600431), we get a palindrome (2650660562).

The spelling of 1340060131 in words is "one billion, three hundred forty million, sixty thousand, one hundred thirty-one".