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13400626241 is a prime number
BaseRepresentation
bin11000111101011110…
…10101010001000001
31021120220122100100102
430132233111101001
5204421030014431
610053421532145
7653036305112
oct143657252101
937526570312
1013400626241
115757338922
12271ba14055
1313573a2352
14911a54209
155366dadcb
hex31ebd5441

13400626241 has 2 divisors, whose sum is σ = 13400626242. Its totient is φ = 13400626240.

The previous prime is 13400626231. The next prime is 13400626243. The reversal of 13400626241 is 14262600431.

13400626241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11678044225 + 1722582016 = 108065^2 + 41504^2 .

It is a cyclic number.

It is not a de Polignac number, because 13400626241 - 214 = 13400609857 is a prime.

It is a Sophie Germain prime.

Together with 13400626243, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13400626243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700313120 + 6700313121.

It is an arithmetic number, because the mean of its divisors is an integer number (6700313121).

Almost surely, 213400626241 is an apocalyptic number.

It is an amenable number.

13400626241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13400626241 is an equidigital number, since it uses as much as digits as its factorization.

13400626241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

The spelling of 13400626241 in words is "thirteen billion, four hundred million, six hundred twenty-six thousand, two hundred forty-one".