Base | Representation |
---|---|
bin | 11110011110000110101011… |
… | …000010011001010001011111 |
3 | 122120111020121100200101211111 |
4 | 132132012223002121101133 |
5 | 120031110233344243424 |
6 | 1153003224344002451 |
7 | 40140625204346152 |
oct | 3636065302312137 |
9 | 576436540611744 |
10 | 134010144134239 |
11 | 397774237aa00a |
12 | 13044092160427 |
13 | 59a1143b950c9 |
14 | 25141a885dc99 |
15 | 1075da0dd3194 |
hex | 79e1ab09945f |
134010144134239 has 2 divisors, whose sum is σ = 134010144134240. Its totient is φ = 134010144134238.
The previous prime is 134010144134233. The next prime is 134010144134327. The reversal of 134010144134239 is 932431441010431.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134010144134239 is a prime.
It is a super-2 number, since 2×1340101441342392 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134010144134233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67005072067119 + 67005072067120.
It is an arithmetic number, because the mean of its divisors is an integer number (67005072067120).
Almost surely, 2134010144134239 is an apocalyptic number.
134010144134239 is a deficient number, since it is larger than the sum of its proper divisors (1).
134010144134239 is an equidigital number, since it uses as much as digits as its factorization.
134010144134239 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 40.
The spelling of 134010144134239 in words is "one hundred thirty-four trillion, ten billion, one hundred forty-four million, one hundred thirty-four thousand, two hundred thirty-nine".
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