13401025414142 has 16 divisors (see below), whose sum is σ = 20446610511600. Its totient is φ = 6586443134400.

The previous prime is 13401025414097. The next prime is 13401025414157. The reversal of 13401025414142 is 24141452010431.

It is a super-4 number, since 4×13401025414142⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13401025414099 and 13401025414108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 238611167 + ... + 238667322.

It is an arithmetic number, because the mean of its divisors is an integer number (1277913156975).

Almost surely, 2^{13401025414142} is an apocalyptic number.

13401025414142 is a deficient number, since it is larger than the sum of its proper divisors (7045585097458).

13401025414142 is a wasteful number, since it uses less digits than its factorization.

13401025414142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 477278731.

The product of its (nonzero) digits is 15360, while the sum is 32.

Adding to 13401025414142 its reverse (24141452010431), we get a palindrome (37542477424573).

The spelling of 13401025414142 in words is "thirteen trillion, four hundred one billion, twenty-five million, four hundred fourteen thousand, one hundred forty-two".