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1340104300421 is a prime number
BaseRepresentation
bin10011100000000100011…
…100001101011110000101
311202010001011200000000012
4103200010130031132011
5133424013200103141
62503345130000005
7165551014415135
oct23400434153605
94663034600005
101340104300421
11477375a39727
1219787a276005
13994a9967a13
1448c0b946ac5
1524cd4b60ceb
hex1380470d785

1340104300421 has 2 divisors, whose sum is σ = 1340104300422. Its totient is φ = 1340104300420.

The previous prime is 1340104300387. The next prime is 1340104300459. The reversal of 1340104300421 is 1240034010431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1274552939521 + 65551360900 = 1128961^2 + 256030^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340104300421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340104500421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670052150210 + 670052150211.

It is an arithmetic number, because the mean of its divisors is an integer number (670052150211).

Almost surely, 21340104300421 is an apocalyptic number.

It is an amenable number.

1340104300421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340104300421 is an equidigital number, since it uses as much as digits as its factorization.

1340104300421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1340104300421 its reverse (1240034010431), we get a palindrome (2580138310852).

The spelling of 1340104300421 in words is "one trillion, three hundred forty billion, one hundred four million, three hundred thousand, four hundred twenty-one".