1340113110047 has 2 divisors, whose sum is σ = 1340113110048. Its totient is φ = 1340113110046.

The previous prime is 1340113109983. The next prime is 1340113110079. The reversal of 1340113110047 is 7400113110431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340113110047 - 2⁶ = 1340113109983 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340113109998 and 1340113110025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340113110647) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670056555023 + 670056555024.

It is an arithmetic number, because the mean of its divisors is an integer number (670056555024).

Almost surely, 2^{1340113110047} is an apocalyptic number.

1340113110047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340113110047 is an equidigital number, since it uses as much as digits as its factorization.

1340113110047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 1340113110047 its reverse (7400113110431), we get a palindrome (8740226220478).

The spelling of 1340113110047 in words is "one trillion, three hundred forty billion, one hundred thirteen million, one hundred ten thousand, forty-seven".