1340113231231 has 16 divisors (see below), whose sum is σ = 1370615823360. Its totient is φ = 1309694663520.

The previous prime is 1340113231087. The next prime is 1340113231243. The reversal of 1340113231231 is 1321323110431.

It is a cyclic number.

It is not a de Polignac number, because 1340113231231 - 2²⁹ = 1339576360319 is a prime.

It is a super-2 number, since 2×1340113231231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340113231196 and 1340113231205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340113238231) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 200282596 + ... + 200289286.

It is an arithmetic number, because the mean of its divisors is an integer number (85663488960).

Almost surely, 2^{1340113231231} is an apocalyptic number.

1340113231231 is a deficient number, since it is larger than the sum of its proper divisors (30502592129).

1340113231231 is an equidigital number, since it uses as much as digits as its factorization.

1340113231231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12294.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1340113231231 its reverse (1321323110431), we get a palindrome (2661436341662).

The spelling of 1340113231231 in words is "one trillion, three hundred forty billion, one hundred thirteen million, two hundred thirty-one thousand, two hundred thirty-one".