Base | Representation |
---|---|
bin | 11110011110000111110111… |
… | …101100000000100010011101 |
3 | 122120111100220222110210211211 |
4 | 132132013313230000202131 |
5 | 120031120402102031024 |
6 | 1153004000122544421 |
7 | 40141002111103525 |
oct | 3636076754004235 |
9 | 576440828423754 |
10 | 134011430111389 |
11 | 39777a23699746 |
12 | 13044390968111 |
13 | 59a12ba43042c |
14 | 251428b570685 |
15 | 1075e28c53594 |
hex | 79e1f7b0089d |
134011430111389 has 2 divisors, whose sum is σ = 134011430111390. Its totient is φ = 134011430111388.
The previous prime is 134011430111369. The next prime is 134011430111399. The reversal of 134011430111389 is 983111034110431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 125612203059225 + 8399227052164 = 11207685^2 + 2898142^2 .
It is a cyclic number.
It is not a de Polignac number, because 134011430111389 - 213 = 134011430103197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134011430111369) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67005715055694 + 67005715055695.
It is an arithmetic number, because the mean of its divisors is an integer number (67005715055695).
Almost surely, 2134011430111389 is an apocalyptic number.
It is an amenable number.
134011430111389 is a deficient number, since it is larger than the sum of its proper divisors (1).
134011430111389 is an equidigital number, since it uses as much as digits as its factorization.
134011430111389 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 40.
The spelling of 134011430111389 in words is "one hundred thirty-four trillion, eleven billion, four hundred thirty million, one hundred eleven thousand, three hundred eighty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •