134011511 has 2 divisors, whose sum is σ = 134011512. Its totient is φ = 134011510.

The previous prime is 134011499. The next prime is 134011519. The reversal of 134011511 is 115110431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134011511 - 2¹⁸ = 133749367 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134011511.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134011519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67005755 + 67005756.

It is an arithmetic number, because the mean of its divisors is an integer number (67005756).

Almost surely, 2^134011511 is an apocalyptic number.

134011511 is a deficient number, since it is larger than the sum of its proper divisors (1).

134011511 is an equidigital number, since it uses as much as digits as its factorization.

134011511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 134011511 is about 11576.3340915853. The cubic root of 134011511 is about 511.7376471159.

Adding to 134011511 its reverse (115110431), we get a palindrome (249121942).

The spelling of 134011511 in words is "one hundred thirty-four million, eleven thousand, five hundred eleven".