Base | Representation |
---|---|
bin | 11000111101100011… |
… | …00011101000111111 |
3 | 1021120221201222022011 |
4 | 30132301203220333 |
5 | 204421202200112 |
6 | 10053442232051 |
7 | 653044254235 |
oct | 143661435077 |
9 | 37527658264 |
10 | 13401209407 |
11 | 57576a6a83 |
12 | 2720055627 |
13 | 1357547911 |
14 | 911b66955 |
15 | 5367a3aa7 |
hex | 31ec63a3f |
13401209407 has 2 divisors, whose sum is σ = 13401209408. Its totient is φ = 13401209406.
The previous prime is 13401209363. The next prime is 13401209441. The reversal of 13401209407 is 70490210431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13401209407 - 227 = 13266991679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13401209207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700604703 + 6700604704.
It is an arithmetic number, because the mean of its divisors is an integer number (6700604704).
Almost surely, 213401209407 is an apocalyptic number.
13401209407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401209407 is an equidigital number, since it uses as much as digits as its factorization.
13401209407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 13401209407 its reverse (70490210431), we get a palindrome (83891419838).
The spelling of 13401209407 in words is "thirteen billion, four hundred one million, two hundred nine thousand, four hundred seven".
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