Base | Representation |
---|---|
bin | 11000111101100011… |
… | …00100010011101101 |
3 | 1021120221202010001102 |
4 | 30132301210103231 |
5 | 204421202242031 |
6 | 10053442252445 |
7 | 653044265222 |
oct | 143661442355 |
9 | 37527663042 |
10 | 13401212141 |
11 | 57576a9039 |
12 | 2720057125 |
13 | 1357548c35 |
14 | 911b67949 |
15 | 5367a47cb |
hex | 31ec644ed |
13401212141 has 2 divisors, whose sum is σ = 13401212142. Its totient is φ = 13401212140.
The previous prime is 13401212119. The next prime is 13401212159. The reversal of 13401212141 is 14121210431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12915186025 + 486026116 = 113645^2 + 22046^2 .
It is a cyclic number.
It is not a de Polignac number, because 13401212141 - 214 = 13401195757 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13401212191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700606070 + 6700606071.
It is an arithmetic number, because the mean of its divisors is an integer number (6700606071).
Almost surely, 213401212141 is an apocalyptic number.
It is an amenable number.
13401212141 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401212141 is an equidigital number, since it uses as much as digits as its factorization.
13401212141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 13401212141 its reverse (14121210431), we get a palindrome (27522422572).
The spelling of 13401212141 in words is "thirteen billion, four hundred one million, two hundred twelve thousand, one hundred forty-one".
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