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13401212141 is a prime number
BaseRepresentation
bin11000111101100011…
…00100010011101101
31021120221202010001102
430132301210103231
5204421202242031
610053442252445
7653044265222
oct143661442355
937527663042
1013401212141
1157576a9039
122720057125
131357548c35
14911b67949
155367a47cb
hex31ec644ed

13401212141 has 2 divisors, whose sum is σ = 13401212142. Its totient is φ = 13401212140.

The previous prime is 13401212119. The next prime is 13401212159. The reversal of 13401212141 is 14121210431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12915186025 + 486026116 = 113645^2 + 22046^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401212141 - 214 = 13401195757 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401212191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700606070 + 6700606071.

It is an arithmetic number, because the mean of its divisors is an integer number (6700606071).

Almost surely, 213401212141 is an apocalyptic number.

It is an amenable number.

13401212141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401212141 is an equidigital number, since it uses as much as digits as its factorization.

13401212141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 13401212141 its reverse (14121210431), we get a palindrome (27522422572).

The spelling of 13401212141 in words is "thirteen billion, four hundred one million, two hundred twelve thousand, one hundred forty-one".