1340121323 has 2 divisors, whose sum is σ = 1340121324. Its totient is φ = 1340121322.

The previous prime is 1340121317. The next prime is 1340121329. The reversal of 1340121323 is 3231210431.

It is a balanced prime because it is at equal distance from previous prime (1340121317) and next prime (1340121329).

It is an emirp because it is prime and its reverse (3231210431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340121323 - 2¹² = 1340117227 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340121295 and 1340121304.

It is not a weakly prime, because it can be changed into another prime (1340121329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670060661 + 670060662.

It is an arithmetic number, because the mean of its divisors is an integer number (670060662).

Almost surely, 2^1340121323 is an apocalyptic number.

1340121323 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340121323 is an equidigital number, since it uses as much as digits as its factorization.

1340121323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 1340121323 is about 36607.6675438357. The cubic root of 1340121323 is about 1102.5070429395.

Adding to 1340121323 its reverse (3231210431), we get a palindrome (4571331754).

The spelling of 1340121323 in words is "one billion, three hundred forty million, one hundred twenty-one thousand, three hundred twenty-three".