Base | Representation |
---|---|
bin | 1111111110011… |
… | …01110100001011 |
3 | 100100011112010202 |
4 | 13333031310023 |
5 | 233301342141 |
6 | 21144202415 |
7 | 3215041016 |
oct | 777156413 |
9 | 310145122 |
10 | 134012171 |
11 | 69712367 |
12 | 38a6940b |
13 | 219c1a57 |
14 | 13b2637d |
15 | bb7249b |
hex | 7fcdd0b |
134012171 has 2 divisors, whose sum is σ = 134012172. Its totient is φ = 134012170.
The previous prime is 134012129. The next prime is 134012227. The reversal of 134012171 is 171210431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134012171 is a prime.
It is a super-2 number, since 2×1340121712 = 35918523952266482, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134012971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006085 + 67006086.
It is an arithmetic number, because the mean of its divisors is an integer number (67006086).
Almost surely, 2134012171 is an apocalyptic number.
134012171 is a deficient number, since it is larger than the sum of its proper divisors (1).
134012171 is an equidigital number, since it uses as much as digits as its factorization.
134012171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168, while the sum is 20.
The square root of 134012171 is about 11576.3625979839. The cubic root of 134012171 is about 511.7384872086.
The spelling of 134012171 in words is "one hundred thirty-four million, twelve thousand, one hundred seventy-one".
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