Base | Representation |
---|---|
bin | 1100001100000011011100… |
… | …0001001100010101111001 |
3 | 1202110010220010122022001222 |
4 | 3003000313001030111321 |
5 | 3224031200040214342 |
6 | 44300234055321425 |
7 | 2552130515130455 |
oct | 303006701142571 |
9 | 52403803568058 |
10 | 13401221023097 |
11 | 42a7475997896 |
12 | 16052b5980275 |
13 | 76296426bc1b |
14 | 3448a042b665 |
15 | 1838e336eed2 |
hex | c303704c579 |
13401221023097 has 2 divisors, whose sum is σ = 13401221023098. Its totient is φ = 13401221023096.
The previous prime is 13401221023049. The next prime is 13401221023121. The reversal of 13401221023097 is 79032012210431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12934819443001 + 466401580096 = 3596501^2 + 682936^2 .
It is a cyclic number.
It is not a de Polignac number, because 13401221023097 - 26 = 13401221023033 is a prime.
It is not a weakly prime, because it can be changed into another prime (13401221023397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700610511548 + 6700610511549.
It is an arithmetic number, because the mean of its divisors is an integer number (6700610511549).
Almost surely, 213401221023097 is an apocalyptic number.
It is an amenable number.
13401221023097 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401221023097 is an equidigital number, since it uses as much as digits as its factorization.
13401221023097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 35.
The spelling of 13401221023097 in words is "thirteen trillion, four hundred one billion, two hundred twenty-one million, twenty-three thousand, ninety-seven".
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