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13401221023397 is a prime number
BaseRepresentation
bin1100001100000011011100…
…0001001100011010100101
31202110010220010122022111002
43003000313001030122211
53224031200040222042
644300234055323045
72552130515131364
oct303006701143245
952403803568432
1013401221023397
1142a7475998039
1216052b5980485
1376296426c0bc
143448a042b7db
151838e3370132
hexc303704c6a5

13401221023397 has 2 divisors, whose sum is σ = 13401221023398. Its totient is φ = 13401221023396.

The previous prime is 13401221023291. The next prime is 13401221023427. The reversal of 13401221023397 is 79332012210431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10902880406401 + 2498340616996 = 3301951^2 + 1580614^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13401221023397 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13401221023397.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401221023097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700610511698 + 6700610511699.

It is an arithmetic number, because the mean of its divisors is an integer number (6700610511699).

Almost surely, 213401221023397 is an apocalyptic number.

It is an amenable number.

13401221023397 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401221023397 is an equidigital number, since it uses as much as digits as its factorization.

13401221023397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 38.

The spelling of 13401221023397 in words is "thirteen trillion, four hundred one billion, two hundred twenty-one million, twenty-three thousand, three hundred ninety-seven".