Base | Representation |
---|---|
bin | 10011100000000110000… |
… | …010001000010001110111 |
3 | 11202010010000221101102111 |
4 | 103200012002020101313 |
5 | 133424042020032342 |
6 | 2503351522351451 |
7 | 165551460462406 |
oct | 23400602102167 |
9 | 4663100841374 |
10 | 1340131017847 |
11 | 47738a027946 |
12 | 1978871bb587 |
13 | 994b236084b |
14 | 48c112dd63d |
15 | 24cd718c217 |
hex | 13806088477 |
1340131017847 has 2 divisors, whose sum is σ = 1340131017848. Its totient is φ = 1340131017846.
The previous prime is 1340131017809. The next prime is 1340131017851. The reversal of 1340131017847 is 7487101310431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1340131017847 is a prime.
It is a super-2 number, since 2×13401310178472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340131017887) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670065508923 + 670065508924.
It is an arithmetic number, because the mean of its divisors is an integer number (670065508924).
Almost surely, 21340131017847 is an apocalyptic number.
1340131017847 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340131017847 is an equidigital number, since it uses as much as digits as its factorization.
1340131017847 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56448, while the sum is 40.
The spelling of 1340131017847 in words is "one trillion, three hundred forty billion, one hundred thirty-one million, seventeen thousand, eight hundred forty-seven".
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