1340131120000 has 320 divisors, whose sum is σ = 3506354794800. Its totient is φ = 509386752000.

The previous prime is 1340131119991. The next prime is 1340131120021. The reversal of 1340131120000 is 211310431.

It is a tau number, because it is divible by the number of its divisors (320).

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 127274736 + ... + 127285264.

Almost surely, 2^{1340131120000} is an apocalyptic number.

1340131120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1340131120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1753177397400).

1340131120000 is an abundant number, since it is smaller than the sum of its proper divisors (2166223674800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340131120000 is an equidigital number, since it uses as much as digits as its factorization.

1340131120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10643 (or 10616 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1340131120000 its reverse (211310431), we get a palindrome (1340342430431).

The spelling of 1340131120000 in words is "one trillion, three hundred forty billion, one hundred thirty-one million, one hundred twenty thousand".