134013201431 has 2 divisors, whose sum is σ = 134013201432. Its totient is φ = 134013201430.

The previous prime is 134013201419. The next prime is 134013201451. The reversal of 134013201431 is 134102310431.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134013201431 is a prime.

It is a super-2 number, since 2×134013201431² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134013201397 and 134013201406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134013201451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006600715 + 67006600716.

It is an arithmetic number, because the mean of its divisors is an integer number (67006600716).

Almost surely, 2^134013201431 is an apocalyptic number.

134013201431 is a deficient number, since it is larger than the sum of its proper divisors (1).

134013201431 is an equidigital number, since it uses as much as digits as its factorization.

134013201431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 134013201431 its reverse (134102310431), we get a palindrome (268115511862).

The spelling of 134013201431 in words is "one hundred thirty-four billion, thirteen million, two hundred one thousand, four hundred thirty-one".