Base | Representation |
---|---|
bin | 10011100000000110001… |
… | …110101100001000011111 |
3 | 11202010010021010200000001 |
4 | 103200012032230020133 |
5 | 133424043340413211 |
6 | 2503352121115131 |
7 | 165551530454650 |
oct | 23400616541037 |
9 | 4663107120001 |
10 | 1340134310431 |
11 | 477390976694 |
12 | 197888328aa7 |
13 | 994b2c44417 |
14 | 48c11919527 |
15 | 24cd75dcac1 |
hex | 138063ac21f |
1340134310431 has 32 divisors (see below), whose sum is σ = 1567828224000. Its totient is φ = 1121711136000.
The previous prime is 1340134310423. The next prime is 1340134310453.
1340134310431 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 1340134310431 - 23 = 1340134310423 is a prime.
It is a super-2 number, since 2×13401343104312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1340134310431.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340134310131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 288260595 + ... + 288265243.
It is an arithmetic number, because the mean of its divisors is an integer number (48994632000).
Almost surely, 21340134310431 is an apocalyptic number.
1340134310431 is a deficient number, since it is larger than the sum of its proper divisors (227693913569).
1340134310431 is a wasteful number, since it uses less digits than its factorization.
1340134310431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8199.
The product of its (nonzero) digits is 5184, while the sum is 28.
It can be divided in two parts, 134013 and 4310431, that added together give a palindrome (4444444).
The spelling of 1340134310431 in words is "one trillion, three hundred forty billion, one hundred thirty-four million, three hundred ten thousand, four hundred thirty-one".
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